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blsea [12.9K]
3 years ago
6

I need help. I’m in construction math. I need detailed answers

Mathematics
1 answer:
valina [46]3 years ago
3 0
7 ft 6 in = 90 in
10t ft = 120 in

A = 90 x 120 = 10800 in^2

10800 in^2 = 75 ft^2

answer
C. 75 ft^2

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Answer:   0.09375

Step-by-step explanation:

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Estimate the square root of 0.39 to the nearest 10th Place
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0.62

Step-by-step explanation:

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What is 3*78 using distributive property
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<span>3 x (80 - 2) = 3 x 80 - 3 x 2 = 240 - 6 = 234 is your answer

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4 years ago
A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?
attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: \binom{n}{r}=\frac{n!}{r!(n-r)!}

\binom{8}{3}=\frac{8!}{3!(5)!}=56

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: \binom{8}{3}=\frac{8!}{3!(5)!}=56

For 4 heads: \binom{8}{4}=\frac{8!}{4!(4)!}=70

For 5 heads: \binom{8}{5}=\frac{8!}{5!(3)!}=56

For 6 heads: \binom{8}{6}=\frac{8!}{6!(2)!}=28

For 7 heads: \binom{8}{7}=\frac{8!}{7!(1)!}=8

For 8 heads: \binom{8}{8}=1

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

\binom{8}{4}=\frac{8!}{4!(4)!}=70

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0
3 years ago
52. In exploring possible sites for a convenience store in a large neighborhood, the retail chain wants to know the proportion o
kvasek [131]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.1}{1.96})^2}=96.04  

Then the minimum sample size in order to satisfy the condition of 0.1 for the margin of error is 97 and since the sample used is n =100 we can conclude that is sufficient and the best answer would be:

D. Yes.

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. We know that we require a 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

We want a margin of error of ME =\pm 0.1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior info for the population proportion we can use as estimator the value of 0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.1}{1.96})^2}=96.04  

Then the minimum sample size in order to satisfy the condition of 0.1 for the margin of error is 97 and since the sample used is n =100 we can conclude that is sufficient and the best answer would be:

D. Yes.

4 0
3 years ago
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