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olga2289 [7]
3 years ago
8

Sarah bought 18 eggs from the store. How maany dozen eggs does she buy?

Mathematics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

Sarah brought 1 and 1/2.

Step-by-step explanation:

18 divided by 12= 1 r 6

write the remainder as the numerator over the original denominator you can also make the fraction simple.

1  and 6/12

1 and 1/2

You might be interested in
Find x using the picture below.
Katen [24]

Answer:

x ≈ 14.5

Step-by-step explanation:

A = x²√(25+10√5)/4

A = 1.72a²

x² = A/1.72

= 363.27/1.72

≈ 211

x = √211

≈ 14.5

6 0
3 years ago
If the domain of f(n) = -4n - 3 is (-1, 1/4,4}, what is the range?
ahrayia [7]

Answer:

Range= \{1,-4,-19\}

Step-by-step explanation:

Given

f(n) = -4n - 3

n = \{-1,1/4,4\} --- domain

Required

Determine the range

To do this, we simply substitute the values of n in the given expression

So, we have:

n = -1

f(-1) = -4 * -1 - 3 =4 - 3 = 1

n = 1/4

f(-1) = -4 * 1/4 - 3 =-1 - 3 = -4

n=4

f(-1) = -4 * 4 - 3 =-16 - 3 = -19

Hence, the range is:

Range= \{1,-4,-19\}

5 0
3 years ago
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

Apply substitution to get

y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0
2 years ago
How to know if the problem is side angle side ​
Anuta_ua [19.1K]

Answer:

if you have a pic i may know what you are talking about better and i will try to help you

Step-by-step explanation:

if you are talking about a missing angle of a right triangle i can tell you how to do that

7 0
3 years ago
Why cant bicycles stand up by themselves
Snezhnost [94]
They can, its just very difficult to get them to because their tires aren't solid and flat so the bike can tip easily. their centre of gravity also moves easily so it is very difficult to balance them.

hope this helps :)
5 0
3 years ago
Read 2 more answers
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