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frutty [35]
3 years ago
6

Two boxes have the same volume. One box has a base that is 2 inches by 2 inches. The other box has a base that is 4 inches by 4

inches.
How many times as tall is the box with the smaller base?
Mathematics
2 answers:
Vsevolod [243]3 years ago
7 0

Answer:

It is 4 times as tall

Step-by-step explanation:

lianna [129]3 years ago
3 0

Answer:

4 times as tall.

Step-by-step explanation:

Volume of the box with the smaller base = 2*2* h1 = 4h1 where h1 is its height.

Similarly the volume of the larger base box =  4*4 * h2 = 16h2 with height h2.

So the ratio of their volumes is  16h2 / 4h1 = 4h2 / h1.

Now the volumes are equal so 4h2 = h1.

Therefore   h2 = h1/4  so h1 = 4h2.

The box with the smaller base is 4 times as tall as the other box.

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Answer:

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Step-by-step explanation:

(3c^2d^4)^3 * (2x^5d^8)^3

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Hope this helps!

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swat32

Answer:

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Step-by-step explanation:

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If I could get help thank u
nika2105 [10]

An acute angle is infact 90 degrees, therefore your answer is correct.

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