All categories

3 years ago

If cosA=4/5 and cosB=3/5 then find a,b,c

Mathematics

2 answers:

dexar [7]3 years ago

4 0

Ansnajsnandndnxnxbdsjsjsj

aliya0001 [1]3 years ago

3 0

Answer:

a = 3, b = 4, c = 5

Step-by-step explanation:

Assuming we're working with a right triangle, where c is the hypotenuse, then using the definition of the cosine being the adjacent side over the hypotenuse, then we know:

a = 3, because it is the side adjacent to B

b = 4, because it is the side adjacent to A

c = 5, because it is the denominator in bot fractions

This of course assumes that there is no additional ratio in place. For example, if the lengths were instead 8, 6 and 10 respectively, then the cosines given would still be 4/5 and 3/5. Truthfully these only tell relative sizes of the sides, and not their absolute sizes.

You might be interested in

Directions:Simplify the following monomials.

aleksandrvk [35]

Answer:

See answers below

Step-by-step explanation:

6) 4ab + 13bc (As it is)

7) -6a²b²

8) -3x²

9) 11x²y + 6xy²

10) 8x - (-2x) = 10x

Hope this helps :)

3 0

3 years ago

Can someone give m the answer i don't know what the answer is.

nikklg [1K]

Answer:

it's subtraction (-)

Step-by-step explanation:

can you give me brainliest? I only need one more

7 0

2 years ago

Read 2 more answers

drawbridge at the entrance to an ancient castle is raised and lowered by a pair of chains. The figure represents the drawbridge

jasenka [17]

Answer:

4.0 meters, ∠C = 39°, ∠A = 51°

Step-by-step explanation:

Firstly, our diagram shows us that the given triangle is actually a right triangle. So we can use the <em>Pythagorean Theorem</em> to solve for the height of the chain:

$a^{2} +b^{2} =c^{2}$

$(3.3)^{2} +b^{2} =(5.2)^{2}$

$b^{2} =(5.2)^{2}-(3.3)^{2}$

$b =\sqrt{(5.2)^{2}-(3.3)^{2}}$

$b=4.0187...$

$b=4.0 m$

Now, we can use the <em>Law of Cosines</em> to figure out one of the acute angles:

$c^{2} =a^{2} +b^{2} -2ab(cos(C))$

$(3.3)^{2} =(4.0)^{2} +(5.2)^{2} -2(4.0)(5.2)(cos(C))$

$cos(C)=\frac{(3.3)^{2}-(4.0)^{2} -(5.2)^{2}}{-2(4.0)(5.2)}$

$C=cos^{-1}( \frac{(3.3)^{2}-(4.0)^{2} -(5.2)^{2}}{-2(4.0)(5.2)})$

$C=39.3915...$

∠C = 39°

And since we know that all angles in a triangle add up to 180°:

∠A + ∠B + ∠C = 180

∠A + 90 + 39 = 180

∠A = 180 - 90 - 39

∠A = 51°

However, you should always review any answers on the Internet and make sure they are correct! Check my work to see if I made any mistakes!

7 0

3 years ago

Can the sides of a triangle have lengths 3.5, 10.9, and 14.4?

andrew11 [14]

Answer:

Step-by-step explanation:

A triangle can NOT have those lengths because any side of a triangle has to have a length greater than the sum of the other two sides. In this case, 14.4, one of the sides, is not greater than the sum of the other two sides (which is also 14.4).

Hope this helps :)

4 0

3 years ago

D. Evaluate each of the following. (5 points)

Harrizon [31]

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer: 5/2

============================================

Problem 3

(f o f o f)(1) = f( f(f(1)) )

(f o f o f)(1) = f( (f o f)(1) )

(f o f o f)(1) = f( 5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f( f(f(f(1)) )

(f o f o f o f)(1) = f( (f o f o f)(1) )

(f o f o f o f)(1) = f( 29/10 )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f( f(f(f(f(1)))) )

(f o f o f o f o f)(1) = f( (f o f o f o f)(1) )

(f o f o f o f o f)(1) = f( 941/290 )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

4 0

3 years ago

Read 2 more answers