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vlabodo [156]
3 years ago
6

I REALLY NEED HELP WITH THESE PROBLEMS I WILL AWARD BRAINLIEST

Mathematics
1 answer:
exis [7]3 years ago
5 0

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The volume of a rectangular prism is 2x^3 + 9x^2 - 8x -36 with height x + 2. Using synthetic division, what is the area of the b
Luba_88 [7]

Answer:

Step-by-step explanation:

x+2=0

x=-2

-2 | 2   9    -8  -36

   |      -4  -10   36

______________

   |  2    5  -18  | 0

area= 2x²+5x-18

5 0
3 years ago
What is the equation of the line that passes through the point <br> (−2,0) and has a slope of 5/2?
IRINA_888 [86]

Answer: The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

Step-by-step explanation:

5 0
3 years ago
Find the correct values for the variables that make the statement cos(h)=x/y true.
Stels [109]

Answer:

The sum of the measures of the angles in a triangle is equal to 180 degree.

In triangle FGH;

\angle F + \angle G + \angle H = 180^{\circ}

or

\angle H = 180^{\circ} -{\angle F + \angle G}

Substitute the given values from the given figure we have;

\angle H = 180^{\circ} -{33^{\circ} + 90^{\circ}}

\angle H = 180^{\circ} -{123^{\circ}}

Simplify:

\angle H = 57^{\circ}

Given that:

\cos H = \frac{x}{y}

Using Cosine ratio:

\cos \theta = \frac{\text{Base}}{\text{Hypotenuse}}

In a given figure:

Base = GH = x and Hypotenuse = FH = y = 80 cm

Then;

\cos 57^{\circ}= \frac{x}{80}

or

x = \cos 57^{\circ} \cdot 80  

x = 0.54463903501 \cdot 80 \approx 43.57 cm

Therefore, the value of :

H = 57^{\circ}

x = 43.57 cm

y = 80 cm





5 0
3 years ago
Read 2 more answers
Simplify the rational expression 2X/X and state any values of X where the expression is undefined
Ivahew [28]

Answer:

2 and 0

Step-by-step explanation:

simplification=2x/x=2/1=2

only if the denominator is 0 can afraction be indefined so 0

3 0
3 years ago
F(x) = | 5x + 1 | - 3<br> g(x) = 4 <br><br> Find (f - g) (x)
Slav-nsk [51]

Answer: |5x+1|-7

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)=(|5x+1|-3)-4=\boxed{|5x+1|-7}

7 0
2 years ago
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