Question

If z varies inversely as x^2, and z = 9 when x = 2/3, find z when x = 5/4

Answer 1

Answer:

Step-by-step explanation:

z varies inversely

so z=a/x^2

9=a/(2/3)^2

9=a/(4/9)

9=9a/4

a=4

z=4/x^2

z=4/(5/4)^2

z=4/(25/16)

z=64/25