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kirza4 [7]
3 years ago
5

Explain how to solve X/3 < -2 Please and thank you!

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0
X< -6 is your answer

simplify both sides of the inequality
1/3x<-2
multiply both sides by 3
3x(1/3x)<(3)x(-2)
x<-6
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Determine the value of c so that f(x) is continuous on the entire real line when
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Answer:

A. -4

Step-by-step explanation:

Given the function f(x) = x + 3 for x ≤ -1 and 2x - c for x > -1, for the function to be continuous, the right hand limit of the function must be equal to its left hand limit.

For the left hand limit;

The function at the left hand occurs at x<-1

f-(x) = x+3

f-(-1) = -1+3

f-(-1) = 2

For the right hand limit, the function occurs at x>-1

f+(x) = 2x-c

f+(-1) = 2(-1)-c

f+(-1) = -2-c

For the function f(x) to be continuous on the entire real line at x = -1, then

f-(-1) = f+(-1)

On equating both sides:

2 = -2-c

Add 2 to both sides

2+2 = -2-c+2

4 =-c

Multiply both sides by minus.

-(-c) = -4

c = -4

Hence the value of c so that f(x) is continuous on the entire real line is -4

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