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makkiz [27]
3 years ago
11

Over long periods of time, a series of processes continuously change rocks from one type into another. This is called the rock c

ycle. A combination of subsurface and surface processes are responsible for the recycling of rocks in the geosphere.(that was the story)
What two processes are responsible for changing metamorphic and igneous rock into sedimentary rock?(this is the question)
A) intrusive and extrusive
B) weathering and erosion
C) subduction and sea floor spreading
D) heat and pressure
Chemistry
2 answers:
balandron [24]3 years ago
3 0

Answer:

B) weathering and erosion

Explanation:

The two processes responsible for changing metamorphic and igneous rocks into sedimentary rocks is weathering and erosion.

Weathering is the defined as the physical disintegration and chemical decomposition of rocks to form sediments and soils.

Erosion is the removal of weathered materials from the surface of the earth.

The process of erosion and weathering serves to convert igneous and metamorphic rocks into sediments by which a sedimentary rock is formed.

Genrish500 [490]3 years ago
3 0

Answer: The rock cycle

Explanation: Well its kinda obious that it is the rock cycle because the question says it changes countinuously to other rocks so yeah rock cycle is answer to question.

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a sample of ammonia liberates 5.66 kj of heat as it solidifies at its melting point . what is the mass of the sample?
Reil [10]
The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>

Given that 
ΔHsolid = -5.66 kJ/mol.
This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies 

When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles 

<span>molar mass of NH3 = 17 g/mole </span>
<span>1 mole of NH3 = 17 g </span>
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g
7 0
3 years ago
What will the ratio of ions be in any compound formed from a group 1a and a group 7a nonmetals?
julsineya [31]
Group 1a elements (the first column on the left side of the Periodic table) always release one electron to form positive ions with a charge of +1. Group 7a nonmetals (the <em>second to the last </em>column on the right side- the rightmost column are the noble gases) always desire to gain one electron to form negative ions with a charge of -1.
Since their charges are equal and opposite, they will always combine in a 1:1 ratio.

4 0
3 years ago
2. In contrast to Venus, the coldest temperature yet measured on the surface of
Leviafan [203]

38K

-391°F

Explanation:

Given temperature:

Temperature of Triton = -235°C

Unknown:

Surface temperature of Triton in °F and Kelvin

Solution:

Temperature is the degree of hotness or coldness of a body.

It is usually measured using units of kelvin, degree Celsius and degree Fahrenheit.

tK = 273 + t°C    from °C  to K

t°F = \frac{9}{5} t°C  + 32

 

tk = temperature in kelvin

 t°C = temperature in Celsius

t°F = temperature in Fahrenheit

tK = 273 + (-235) = 38K

t°F = \frac{9}{5} x (-235)   + 32  = -423 + 32 = -391°F

learn more:

Heat and temperature brainly.com/question/914750

#learnwithBrainly

7 0
4 years ago
Sprinkler powder on the carron board _________ friction​
VARVARA [1.3K]

Answer:

Sprinkling of powder on the carom board <u>reduces</u> friction.

5 0
3 years ago
Read 2 more answers
A chemist wishing to do an experiment requiring 47Ca2+(half-life = 4.536 days) needs 5.00 g of the nuclide. What mass of 47CaCO
Artyom0805 [142]

Answer: The answer is 6.78 grams.

Explanation: The equation used for solving this type of problems  is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount of radioactive substance, N is the remaining amount and n is the number of half lives.

Number of half lives is calculated on dividing the given time by the half life.

n = time/half life

Time is given as 48.0 hours and the half life is given as 4.536 days. let's make the units same and for this let's convert the half life from days to hours.

4.536days(\frac{24hours}{1day})

= 108.864 hours

So, n=\frac{48.0}{108.864}  = 0.441

Since 5.00 g is the required amount when the radioactive substance is delivered to the scientist, it would be the final amount that is N. We need to calculate the initial amount. Let's plug in the values in the equation:

\frac{5.00}{N_0}=(\frac{1}{2})^0^.^4^4^1

\frac{5.00g}{N_0}=0.737

N_0=\frac{5.00g}{0.737}

N_0 = 6.78 g

So, 6.78 g of the radioactive substance needs to be ordered.

4 0
4 years ago
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