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Talja [164]
2 years ago
9

Sprinkler powder on the carron board _________ friction​

Chemistry
2 answers:
VARVARA [1.3K]2 years ago
5 0

Answer:

Sprinkling of powder on the carom board <u>reduces</u> friction.

ICE Princess25 [194]2 years ago
4 0

Answer:

Sprinkler powder on the carron board reduce friction.

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Sedimentary rocks are changed to metaphoric rocks through seduction and _____________?
Nana76 [90]
Hello,

Here is your answer:

The proper answer to this question is "deposition".

Your answer deposition.

If you need anymore help feel free to ask me!

Hope this helps!
7 0
3 years ago
Enter the appropriate symbol for an isotope of phosphorus-32 corresponding to the isotope notation AZX. Express your answer as a
Lelechka [254]

Answer:

^{32}_{15}P

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

However, when we talk about the atomic number of the ion, it is not equal to the number of electrons as electron can be gained or loosed.

This is why, more appropriately, the number of the protons which are present in the nucleus of the atom is called the atomic number.

Thus, atomic number of phosphorus = 15

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Given, Mass number = 32

Thus, the symbol of the isotope is:-

^{32}_{15}P

8 0
3 years ago
Which statement correctly contrasts science and pseudoscience
mojhsa [17]
brainly.com/question/1470976 Hope this helps!
8 0
3 years ago
Write equation to represent the Hydrogenation reactions​
garik1379 [7]

Explanation:

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4 0
2 years ago
An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12.
ankoles [38]
Two precursor alkenes

    H₃C  CH₃
         I   I
H₂C=C-CH-CH₃    2,3-dimethyl-1-butene

   H₃C      CH₃
        I       I
H₃C-CH=CH-CH₃    2,3-dimethyl-2-butene


alkane

   H₃C     CH₃
        I      I
H₃C-CH-CH-CH₃    2,3-dimethylbutane

    H₃C  CH₃                        H₃C     CH₃
         I   I                                   I      I
H₂C=C-CH-CH₃  + H₂ → H₃C-CH-CH-CH₃ 
  
    H₃C   CH₃                       H₃C     CH₃
        I    I                                   I      I
H₂C-C=CH-CH₃  + H₂ → H₃C-CH-CH-CH₃ 

6 0
3 years ago
Read 2 more answers
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