439.3 g CO2
Explanation:
First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:
3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)
= 9.981 mol CO2
Use the molar mass of CO2 to determine the # of grams of CO2:
9.981 mol CO2 x (44.01 g CO2/1 mol CO2)
= 439.3 g CO2
Multiply straight across! 3*5*2=30, and 4*6*5=120. So, the answer is 30/120, or 1/4.
Explanation:
: of or relating to the partitioning and cycling of chemical elements and compound's between the living and nonliving part's of an ecosystem.