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3 years ago

Question:

1 answer:

8 0

I think just the "possible" ones, without fully factoring, are based on factors of the last whole number-- +20.
So factors of 20: 1, 2, 4, 5, 10, 20

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Suppose there are n students in a class what is the probability at least two students have same birthday

vitfil [10]

I don't have enough info to solve this

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3 years ago

Read 2 more answers

Identify the ellipses, represented by equations, whose eccentricities are less than 0.5

ozzi

Answer:

See explanation

Step-by-step explanation:

Hello, we cannot see the ellipse equations.

The eccentric of an ellipse is given by:

$e = \frac{c}{a}$

Assuming the equations are:

$\frac{ {x}^{2} }{25} + \frac{ {y}^{2} }{16} = 1$

Then a²=25 and b²=16

${c}^{2} = {a}^{2} - {b}^{2}$

${c}^{2} = 25 - 16$

${c}^{2} = {3}^{2}$

$c = 3$

The eccentricity is:

$e = \frac{3}{5} = 0.6$

If the ellipse has equation,

$\frac{ {x}^{2} }{ {5}^{2} } + \frac{ {y}^{2} }{ {3}^{2} } = 1$

then the this time, we have a=5 and b=3.

This means that:

${c}^{2} = {a}^{2} - {b}^{2}$

${c}^{2} = {5}^{2} - {3}^{2}$

${c}^{2} = {4}^{2}$

$c = 4$

$c = \frac{4}{5} = 0.8$

3 0

3 years ago

Read 2 more answers

If I owe you $1.76 in overtime pay, you receive $19.50 for each hour of OT. How many hours overtime are you owed?

Lady_Fox [76]

Answer: 0.09 hours

Step-by-step explanation:

You are owed $1.76 in overtime pay.

The hourly rate for overtime is $19.50 per hour.

To find the number of hours owed, you need to divide the amount owed by the amount owed per hour.

The number of hours you are owed is therefore:

= Amount owed / Amount owed per hour

= 1.76 / 19.50

= 0.09 hours

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3 years ago

How to solve radical numerator fractions

Nonamiya [84]

Y=radical 3
just cancel out the 2 on both sides

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3 years ago

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of

jarptica [38.1K]

Answer:

The "probability that a given score is less than negative 0.84" is $\\ P(z$ .

Step-by-step explanation:

From the question, we have:

The random variable is normally distributed according to a standard normal distribution, that is, a normal distribution with $\\ \mu = 0$ and $\\ \sigma = 1$ .
We are provided with a z-score of -0.84 or $\\ z = -0.84$ .

Preliminaries

A z-score is a standardized value, i.e., one that we can obtain using the next formula:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Where

x is the raw value coming from a normal distribution that we want to standardize.
And we already know that $\\ \mu$ and $\\ \sigma$ are the mean and the standard deviation, respectively, of the normal distribution.

A z-score represents the distance from $\\ \mu$ in standard deviations units. When the value for z is negative, it "tells us" that the raw score is below $\\ \mu$ . Conversely, when the z-score is positive, the standardized raw score, x, is above the mean, $\\ \mu$ .

Solving the question

We already know that $\\ z = -0.84$ or that the standardized value for a raw score, x, is below $\\ \mu$ in 0.84 standard deviations.

The values for probabilities of the standard normal distribution are tabulated in the standard normal table, which is available in Statistics books or on the Internet and is generally in cumulative probabilities from negative infinity, - $\\ \infty$ , to the z-score of interest.

Well, to solve the question, we need to consult the standard normal table for $\\ z = -0.84$ . For this:

Find the cumulative standard normal table.
In the first column of the table, use -0.8 as an entry.
Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)
The intersection of these two numbers "gives us" the cumulative probability for z or $\\ P(z$ .

Therefore, we obtain $\\ P(z$ for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".

This represent the area under the standard normal distribution, $\\ N(0,1)$ , at the left of z = -0.84.

To "draw a sketch of the region", we need to draw a normal distribution (symmetrical bell-shaped distribution), with mean that equals 0 at the middle of the distribution, $\\ \mu = 0$ , and a standard deviation that equals 1, $\\ \sigma = 1$ .

Then, divide the abscissas axis (horizontal axis) into equal parts of one standard deviation from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).

Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, $\\ -\sigma$ , from it). All the area to the left of this value must be shaded because it represents $\\ P(z$ and that is it.

The below graph shows the shaded area (in blue) for $\\ P(z$ for $\\ N(0,1)$ .

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3 years ago