The answer is 11abc^2 + 12a^2b + 18b^2c because:
14abc^2-3abc^2 is 11abc^2
12a^2b + 0 = 12a^2b
16b^2c +2b^2c = 18b^c
Answer:good for him
Step-by-step explanation:
Answer:
no solution
Step-by-step explanation:
1.4-5-2-3=7-6
2.-1-2-3=7-6
3.-3-3=7-6
4.-6=7-6
5.-6=1
6.since -6=1 is false, there's no solution
Answer:
f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)
Step-by-step explanation:
This isn't really mathematics but I can give you an answer.
Assuming, it's in the dark (cuz in the light, why would you use flash), a person in the photograph can gain a red-eye (in the photo).
The only one I can think of is red eye.
