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Greeley [361]
3 years ago
12

A factory worker can make 14 products in 45 minutes. what is the worker's unit rate?

Mathematics
2 answers:
tia_tia [17]3 years ago
7 0
Divide the number of products by the time.

unit rate = (14 products)/(45 minutes) = 0.311 products/minute

Since there are 60 minutes in an hour, if you want the unit rate in products per hour, just multiply what we got above by 60.

unit rate = 18.667 products/hour
valkas [14]3 years ago
7 0
3.2 minutes per products

divide 14 by 45.0 = 3.2 r 30

hope this helps
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There is a correlation between higher education and greater degrees of both income and job stability. What is one downside of co
pickupchik [31]
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3 0
3 years ago
Read 2 more answers
7/10÷2 5/8<br><br> Do i have to simplify
miv72 [106K]

let's firstly convert the mixed fraction to improper fraction and then divide.

\bf \stackrel{mixed}{2\frac{5}{8}}\implies \cfrac{2\cdot 8+5}{8}\implies \stackrel{improper}{\cfrac{21}{8}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{7}{10}\div \cfrac{21}{8}\implies \cfrac{~~\begin{matrix} 7 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{5}{~~\begin{matrix} 10\\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{4}{~~\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{3}{~~\begin{matrix} 21 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{4}{15}

6 0
3 years ago
Jamal and Martina both have freckles, but their son Maddox does not. Show how this is possible in a Punnett square. If Jamal and
e-lub [12.9K]

Answer:

This is a Biology question.

Probability that each additional child that Jamal and Martina will have freckles is 3/4.

Step-by-step explanation:

The possession of freckles in humans is a dominant trait (FF or Ff) while no freckles is a recessive trait (ff). This means that in the gene responsible for freckles, an individual must possess the dominant allele (F) to possess it. First of all, it is important to note that Jamal and Martina produced a son without freckles (recessive trait) because both parents are heterozygous for the trait i.e. they possess a combination of the dominant (freckles) allele and the recessive (no freckles) allele.

In that case, when Jamal and Martina come together who are both heterozygous (Ff), they produce gametes that have alleles F and f. Using a punnet square (see attachment), four possible offsprings will be produced with genotypes: FF, Ff, Ff, and ff.

The genotypes FF, Ff and Ff will all possess freckles phenotypically while tje genotype ff will not possess freckle. Hence, Maddox by a 1/4 chance must have fallen into this category with genotype (ff).

According to the illustration above, the probability that Jamal and Martina will produce offsprings with freckles is 3/4 (FF, Ff, Ff) while the probability that they will produce offsprings with no freckles is 1/4 (ff). Hence, if they have more children, the probability that each child will possess freckles is 3/4.

See attachment for the punnet square.

7 0
3 years ago
How do i write 14000000000000 using a suitable index?
MakcuM [25]

14x10x10x10x10x10x10x10x10x10x10x10x10= 14^12

3 0
3 years ago
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