Given that the numbers are consecutive:
let the first number be x, the second number will be x+1, the third number be x+2
thus the sum of the numbers will be:
x+(x+1)+(x+2)=-381
3x+3=-381
3x=-381-3
3x=-384
x=-128
thus the first number is -128, the second number is -127 and the third number is -126
Just graph it and you can see if they are parallel, perpendicular, or one solution.
Given:
The system Mx+Ny=P has a solution (1,3) where Rx+Sy=T; <span>M, N, P, R,S and T are non-zero real numbers.
Solve for M, N, R, P, S, T:
M +3N = P
R + 3S = T
The given choices should simplify to the equations above.
A) Mx +Ny = P
7Rx + 7Sy = 7T
7(Rx + Sy) = 7T
Rx + Sy = T
remarks: CORRECT
B) (M+R)x + (N+S)y = P + T
Rx + Sy = T
Mx + Rx + Ny + Sy = P + T
Mx + Ny + T = P + T
Mx + Ny = P
remarks: CORRECT
C) Mx + Ny = P
(2M - R)x + (2N - S)y = P - 2T
2Mx - Rx + 2Ny - Sy = P - 2T
2(Mx + Ny) - (Rx + Sy) = P - 2T
2P - (Rx + Sy) = P - 2T
remarks: INCORRECT
</span>
Isn't a semi-circle half of a circle? (correct me if I'm wrong) (I'm horrible at math but I might be able to help you figure out what the question is asking) Are there any answer questions we can choose from or is it just a short writing question?
The answer is 16, you just have to simply the whole problem
