<em><u>Question:</u></em>
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
<em><u>Answer:</u></em>
The vertical asymptotes are x = 2 or x = -1
<em><u>Solution:</u></em>
Given that,

For vertical asymptotes, set the denominator to zero and then solve the quadratic equation


Thus the vertical asymptotes are x = - 1 and x = 2
The slope is always going to be rise over run so the answer is 3/12 but in simplest form it is 1/4
44 because it goes into both of the numbers twice without going over
I think 20 Did you try googling it?
Answer:
-19561285.5554
Step-by-step explanation: