$\frac{-1}{4}(\frac{-1}{2}x-\frac{3}{4})-\frac{1}{2}(\frac{3}{4}x+\frac{1}{8})\\\\=\frac{-1}{4}*\frac{-1}{2}x-\frac{-1}{4}*\frac{3}{4}-\frac{1}{2}*\frac{3}{4}x-\frac{1}{2}*\frac{1}{8}\\\\=\frac{1}{8}x+\frac{3}{16}-\frac{3}{8}x-\frac{1}{16}\\\\=\frac{1}{8}x-\frac{3}{8}x+\frac{3}{16}-\frac{1}{16}\\\\=\frac{(1-3)x}{8}+\frac{3-1}{16}\\\\=\frac{-2}{8}x+\frac{2}{16}\\\\=\frac{-1}{4}x+\frac{1}{4}$

4 0

3 years ago

FInd three consecutive even integers such that three times the smallest is four more than twice the largest

Oksanka [162]

n, n + 2, n + 4 - three consecutive even integers

3n = 2(n + 4) + 4 |use distributive property

3n = (2)(n) + (2)(4) + 4

3n = 2n + 8 + 4

3n = 2n + 12 |subtract 2n from both sides

n = 12

n + 2 = 12 + 2 = 14

n + 4 = 12 + 4 = 16

Answer: 12, 14, 16.

4 0

3 years ago

Which number is an integer?

olga_2 [115]

The answer is 0.

Hope this helps!

5 0

3 years ago