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Zinaida [17]
3 years ago
6

Which of the relations has a domain of {-5, 0, 5}?

Mathematics
2 answers:
STALIN [3.7K]3 years ago
8 0
B is the correct answer i believe
natulia [17]3 years ago
8 0

Answer:

B

Step-by-step explanation:

its that how you would look like if you were anime sorry was looking at your pf. have a nice day

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Please help quickly this is like the last answer for a test so please help quickly
Ganezh [65]

Answer: b

its a 3.5 degree angle it is b

3 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!!!!!!
Natasha2012 [34]

Answer:

3rd answer EF =  2√13

Step-by-step explanation:

Make a right triangle and use Pythagorean theorem a²+b² = c²

Go from point  F 6 units down till point (1,-3) .From that point go 4 units left till you hit point E.

Triangle has legs a and b that are 6 and 4 units long so 6² + 4² = EF²

36 + 16 =  52

EF² = 52 find √52

EF = √52

There is no √52 as a whole number so rewrite 52 as a product of number who was a √ and the other who doesn't have a √

52 = 4 * 13

EF = √4 * √13 = 2√13

3 0
3 years ago
If f(x) = x^2- 6 and g(x) = 2x – 1, determine the value of (gºf)(-3).
k0ka [10]
I’m not too sure if I did it correct, but the answer I got was -6x^2+36. I just assumed you’d solve it as usual and then multiply (-3) after distributing-2 to x^2-6. Hope this helps.

5 0
2 years ago
two dice are rolled in succession. determine the probability that their sum is 8 or more, given that the first die is a 4 or mor
viva [34]
See the pic for answer. 

8 0
3 years ago
How many integers are there that consist of four digits (from 1000 to 9999) where the first digit is a 5 or an 8 and the third d
Ostrovityanka [42]

Answer:

1600 integers

Step-by-step explanation:

Since we have a four digit number, there are four digit placements.

For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.

For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.

For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.

For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.

So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers

5 0
3 years ago
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