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3 years ago

Simplify the following:

Mathematics

1 answer:

Daniel [21]3 years ago

7 0

Answer:

a. (x⁵)(x⁸)

${x}^{5 + 8}$

${x}^{13}$

b. k9/k2

$k {}^{9 - 2}$

${k}^{7}$

c. (w⁶)³

${w}^{6 \times 3}$

${w}^{18}$

d. (53)(54)

$53 \times 54 = 2862$

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Due tomorrow plz help. D-F3

Nostrana [21]

D.
slope = -3
passing thru(4,3)
y = mx + b
3 = -3(4) + b
b = 15

equation
y = -3x + 15

E.
(4,5)(6,9)
slope = (9-5)/(6-4) = 4/2 = 2
passing thru (4,5)(6,9)
y = mx + b
5 = 2(4) + b
b = -3

equation
y = 2x - 3

8 0

2 years ago

Rosie is a real estate agent and is paid the following for commission on sales: 4% for the first $50,000, 2% for the next $100,0

Elena-2011 [213]

Answer:

22,000

Step-by-step explanation:

4%/100=0.04

0.04*50,000=20,000 || 130,000-50,000=80,000 ||

2%/100=0.02

0.02*100,000= 2,000 || 80,000 - 100,000 ||

To explain it simply, Rosie receives 20,000 in commission for the first 50,000 of the sale. However, she sold a property for 130,000 meaning she also receives 2,000 for the next 100,000. Therefore she receives $22,000 in total on her $130,000 sale.

6 0

3 years ago

I NEED HELP:

Dmitry_Shevchenko [17]

I believe it's b.

Hope this helped!

6 0

2 years ago

Read 2 more answers

Which of the following is the same formula as A = 6s2 ?

Yuki888 [10]

Answer:

S.A = 6 $s^{2}$

<h2>Please mark my answer as brainliest for further answers :)</h2>

8 0

2 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago