The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
Answer: Choice B
The more trials you do, the closer the empirical probability should get to the theoretical probability. It won't be a perfect match but it will likely be close enough so to speak. Note how 70/420 = 1/6.
5/20 can also be represented as 25/100 or 25%. The can be done by multiplying the top and bottom both by 5 and then dividing our numerator (25) by our denominator(100) to get the %.