Answer:
0.13% of customers spend more than 46 minutes
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What percentage of customers spend more than 46 minutes?
This is 1 subtracted by the pvalue of Z when X = 46. So
has a pvalue of 0.9987
1 - 0.9987 = 0.0013
0.13% of customers spend more than 46 minutes
5pi/12 radians
The arc measure is 75, so theta must also be the same. if theta is 75, and 75 in radians is 5pi/12 radians, then the answer is that.
Answer:
algebra
Step-by-step explanation:- x - 8.
brainliest plzzz
Answer:
Step-by-step explanation:
35% means 35 per hundred. 35/100. simplify and write as 7/20.
0.64 means its 2 zeros left of regular number. 64/100.
82% means 82 per hundred. 82/100. move decimal 2 spaces to left (division is left, multiplication is right). 0.82.
4/5. try to make denominator 100. multiply both numerator and denominator by 20. 80/100. move decimal 2 spaces to the left. 0.8.
14/50. try to make denominator 100. multiply both numerator and denominator by 2. 28/100. 28%
0.19 can be written as 19/100. 19%
