A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?
The positive whole-number factors of 30 are:
1, 2, 3, 5, 6, 10, 15 and 30.
So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that
P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors
=38=3×.125=.375
Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.
For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

In this problem:
- 95% pass final inspection, hence

- 120 components are inspected in one day, hence
.
The variance is given by:

The variance of the number that pass inspection in one day is 5.7.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
just look at the algebra formula and simplify to get your answer. Remember to use your powers well
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