Answer:
Step-by-step explanation:
Step-by-step explanation:
I am only sure about the first one but as for the rest I am not really but I tried...if you need explanations to the first one feel free to ask me
Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Answer:
x = 28
m∠ACD = 68°
Step-by-step explanation:
∠BAE ≅∠DAC because they are vertical angles
∠ACD = 180 - 124 = 56°
to find 'x': 56 + 2x + (180 - 4x) = 180
236 - 2x = 180
-2x = -56
x = 28
m∠ACD = 180 - 4(28) = 180 - 112 = 68°
8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104
