Question

Evaluate the given integral by changing to polar coordinates.

Answer 1

In polar coordinate, R is the set of points

{(r, θ) | 1 < r < 5 and 0 < θ < π/2}

So the integral is

$\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA = \int_0^{\frac\pi2}\int_1^5 r\sin(r^2)\,\mathrm dr\,\mathrm d\theta$

$=\displaystyle\frac\pi2\int_1^5 r\sin(r^2)\,\mathrm dr$

$=\displaystyle\frac\pi4\int_1^5 2r\sin(r^2)\,\mathrm dr$

$=\displaystyle\frac\pi4\int_1^{25} \sin(s)\,\mathrm ds$

(where s = r ²)

$=\displaystyle-\frac\pi4\cos(s)\bigg|_1^{25}= \boxed{\dfrac\pi4 (\cos(1) - \cos(25))}$