All categories

3 years ago

What's the value of the expression 10/12 + (- 8/9)

Mathematics

1 answer:

Pani-rosa [81]3 years ago

3 0

Answer: -1/18 im pretty sure

Step-by-step explanation: Find the exact value using trigonometric identities.

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Z 3 - 2z 2 + 9z - 18.

aev [14]

group the 1st 2 terms and last 2 terms:

(Z63 -2z^2) + (9z-18)

factor out GCF:

z^2(z-2) + 9(z-2)

now factor the polynomial:

(z-2) (z^2+9)

5 0

3 years ago

Read 2 more answers

Brian correctly use a method of completing the square to solve the equation X a 2nd plus 7X -11 equals zero Brian‘s first step w

ArbitrLikvidat [17]

Answer:

$(\frac{7}{2})^{2}$

Step-by-step explanation:

Brain correctly use a method of completing the square to solve the equation:

$x^2+7x-11=0$

His First Step is to: Take the Constant Term to the Right Hand Side

$x^2+7x=11$

The Next Step Would be to:

Divide the Coefficient of x by 2
Square It
Add it to both Sides

In this case, the Coefficient of x = 7

Divided by 2 = $\frac{7}{2}$

Squaring It, we have: $(\frac{7}{2})^{2}$

It is this number $(\frac{7}{2})^{2}$ that is added to both sides in the manner below:

$x^2+7x+(\frac{7}{2})^{2}=11+(\frac{7}{2})^{2}$

6 0

4 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

PLEASE HELP, I'LL MARK BRAINLIEST 3 QUESTIONS.... 36 POINTS!!! i'll help w/ any other subject or if u need anything i just need

Tomtit [17]

Answer:

Step-by-step explanation:

What give me the question

3 0

4 years ago

NEED HELP ASAP!!!!!!!

Elan Coil [88]

I think the answer is C

3 0

3 years ago