Question

How would you solve this?

Answer 1

It would have 3 solutions
if you solve the equation how it is, it give 1 solution but if you make the 1 negative you get 2 more possibilities

Answer 2

Answer:

The equation has three solutions:

x= $\frac{1}{2} + \frac{1}{2} log_{2} (3)$

x=1    

x = $\frac{1}{2}$

Step-by-step explanation:

||$4^{x} - 3$|$-2$| = 1

|$4^{x} - 3$|$-2$ = 1                                                |$4^{x} - 3$|$-2$ = - 1

|$4^{x} - 3$| = 1+2                                                 |$4^{x} - 3$| = -1+2

|$4^{x} - 3$|=3                                                       |$4^{x} - 3$| = 1

$4^{x} - 3$ =3                 $4^{x} - 3$ = - 3                     $4^{x} - 3$ = 1                 $4^{x} - 3$ = - 1

x= $\frac{1}{2} + \frac{1}{2} log_{2} (3)$        x∉∅                                x=1                           $x = \frac{1}{2}$

The union of these four solutions is: $\frac{1}{2} , 1,$ $\frac{1}{2} + \frac{1}{2} log_{2} (3)$

I hope this is clearly and understandably written to you :)