Where does change management play a major role in transforming a client
1 answer:
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Answer:
Here is the C++ program:
#include<iostream> //to use input output functions
#include <math.h> //to use sqrt and pow function
#include<iomanip> //to use setprecision
using namespace std; //to identify objects cin cout
struct Point { // structure name
float x,y; // member variables
};
float calculateDistance (Point a, Point b) { //function that that takes two parameters of type Point
float distance; //stores the distance between two points
distance=sqrt(pow(a.x-b.x,2)+pow(a.y-b.y,2)); //formula to compute distance between two points
return distance; } //returns the computed distance
int main() { //start of main function
Point p1,p2; //creates objects of Point
cout<<"Enter point 1 coordinates: "<<endl; //prompts user to enter the value for coordinates of first point
cin>>p1.x; //reads input value of x coordinate of point 1 (p1)
cin>>p1.y; //reads y coordinate of point 1 (p1)
cout<<"Enter point 2 coordinates: "<<endl; //prompts user to enter the value for coordinates of second point
cin>>p2.x; //reads input value of x coordinate of point 2 (p2)
cin>>p2.y; //reads y coordinate of point 2 (p2)
cout<<"The distance between two points is "<<fixed<<setprecision(2)<<calculateDistance(p1,p2);} //calls function by passing p1 and p2 to compute the distance between p1 and p2 and display the result (distance) up to 2 decimal places
Explanation:
The program has a structure named Point that represents a two-dimensional Cartesian coordinate (x, y). The member variables of this struct are x and y, which are both floating-point values. A function called calculateDistance takes two parameters, a and b of type Pointer and returns the distance between the two given points using formula:
It uses pow function to compute the power of 2 and sqrt function to compute the square root.
Then in main() method the program prompts the user to enter coordinates for two points and calls calculateDistance method to compute the distance between two points and display the result up to 2 decimal places using setprecision(2).
The program along with the output is attached in a screenshot.
