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dybincka [34]
3 years ago
9

PLEASE HELP!! Find the value of x. Round your answer to the nearest tenth.

Mathematics
2 answers:
Setler [38]3 years ago
8 0

Answer:

12.4

Step-by-step explanation:

Tems11 [23]3 years ago
6 0

Answer:

Step-by-step explanation:

Rearrange this to solve for x first:

x=12tan(46) then plug it into your calculator to get

x = 12.4

Make sure your calculator is in degree mode and not radian mode!

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jekas [21]

it would be a, b, and c because if you look at the question and the answers, 3 of the four answers match the 3 of the 4 coordinates

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One hundred adults were asked to name their favorite sport and the results are shown in the circle graph. What sport was preferr
artcher [175]

Answer:

Basketball

38% of adults preferred this sport.

Since 38 out of a 100 is 38 percent.


7 0
3 years ago
Find the length of the missing leg of a right triangle whose hypotenuse measures 15 cm and whose other leg measures 13 cm. geome
Jet001 [13]

Answer:

you can always use sin or cos or tan in these situations

3 0
3 years ago
What is the area of the kite?
enot [183]

The area of the kite is 2.25 square feet

<h3>How to determine the area of the kite?</h3>

The area of the kite is calculated using:

Area = 0.5 * pq

Where p and q are the diagonals of the kite.

In this figure,

p = 3

q = 0.75 * 2 = 1.5

So, we have:

Area = 0.5 * 3 * 1.5

Evaluate

Area = 2.25

Hence, the area of the kite is 2.25

Read more about areas at:

brainly.com/question/24487155

#SPJ1

4 0
2 years ago
Help me please. <br>Help me please. <br>Help me please.
Gnesinka [82]
A)
To be similar triangles have to have equal angles
triangle ZDB' 
1)angle Z=90 degrees
triangle B'CQ
1) angle C 90 degrees

angle A'B'Q=90
DB'Z+A'B'Q+CB'Q=180, straight angle
DB'Z+90+CB'Q=180
DB'Z+CB'Q=90

triangle ZDB'
DZB'+DB'Z=180-90=90

DB'Z+CB'Q=90
DZB'+DB'Z=90
DB'Z+CB'Q=DZB'+DB'Z
2)CB'Q=DZB' (these angles from two triangles ZDB' and B'CQ )
3)so,angles DB'Z and B'QC are going to be equal because of sum of three angles in triangles =180 degrees and 2 angles already equal.
so this triangles are similar by tree angles
b)
B'C:B'D=3:4
B'D:DZ=3:2
CQ-?
DC=AB=21
DC=B'C+B'D (3+4= 7 parts)
21/7=3
B'C=3*3=9
B'D=3*4=12
B'D:DZ=3:2
12:DZ=3:2
DZ=12*2/3=8
B'D:DZ=CQ:B'C
3:2=CQ:9
CQ=3*9/2=27/2

c)
BC=BQ+QC=B'Q+QC
BQ' can be found by pythagorean theorem



3 0
3 years ago
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