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dybincka [34]
3 years ago
9

PLEASE HELP!! Find the value of x. Round your answer to the nearest tenth.

Mathematics
2 answers:
Setler [38]3 years ago
8 0

Answer:

12.4

Step-by-step explanation:

Tems11 [23]3 years ago
6 0

Answer:

Step-by-step explanation:

Rearrange this to solve for x first:

x=12tan(46) then plug it into your calculator to get

x = 12.4

Make sure your calculator is in degree mode and not radian mode!

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What is the perimeter in units of this rectangle?
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16 units. The long side is 7. And the short sides are 1. 7+1=8. Then you would multiply that by 2. Since each value should represent two sides. You get 16 after that
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What is 6/10 divided by 2/5
babunello [35]

Answer:3/2

Step-by-step explanation:

6/10 ➗ 2/5

6/10 x 5/2

(6x5)/(10x2)

30/20=3/2

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It costs $0.60 to run a fan for 4 hours. How much does it<br> cost to run the fan for 6 hours?
spin [16.1K]

Answer:

0.90$

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4hour=0.60

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5 0
3 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
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