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jarptica [38.1K]
3 years ago
9

Find the coordinates of the midpoint of each segment and find the length of each segment

Mathematics
1 answer:
Tasya [4]3 years ago
3 0

Answer:

Is this the whole question or u cut it?

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Find the product of:
eduard

Answer:

144/5

Step-by-step explanation:

\large \rm \: 9 \frac{2}{3} \times 1 \frac{1}{29} \times \frac{6}{15 } \times 7 \frac{1}{5}  \\  =  \frac{29}{3}  \times  \frac{30}{29}  \times  \frac{6}{15}  \times  \frac{36}{5}  \\  = 10 \times  \frac{216}{75}  \\  =  \frac{2160}{75}  \\  =  \frac{144}{5}

5 0
3 years ago
Read 2 more answers
Find the area of the triange with the given vertices A(0,4), B(0,0), C(2,0)
guapka [62]
The height is 4 - 0 = 4, and the base is 2 - 0 = 2. We use the area of the triangle formula, (1/2)(b)(h) = (1/2)(4)(2) = 4.
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Hope this helps!
8 0
4 years ago
Who was the 2nd president
iris [78.8K]
The 2nd president of the United States was John Adams.
3 0
3 years ago
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A counter in Brendan's kitchen is 1 yard wide and 3 yards long. Brendan wants to replace the counter with a granite countertop,
brilliants [131]

Answer:

The new granite countertop will cost $824.

Step-by-step explanation:

Step 1: The problem is to determine how many yards per square that the countertop is made up of.

This is the equivalent of finding the square area of the countertop.

The formula for the square area of a rectangle is given as L x W.

Where L = Lenght which is equal to 3 yards

W = 1 yard

Step 2:

Cost of per square yard required therefore is

3 x 1 = 3 square Yards.

The granite required for the countertop project therefore will cost:

$206 x 3 = $824.00

Cheers!

8 0
3 years ago
Angle A is circumscribed about circle O what is the length of AB
Nana76 [90]

Answer:

AB \approx 4.054

Step-by-step explanation:

The trigonometric equations associated with the figure are, respectively:

AB = 4\cdot \cos 73^{\circ} + 3\cdot \cos \alpha

4\cdot \sin 73^{\circ} = 3 +3\cdot \sin \alpha

The components with the unknown angle are cleared and used in the fundamental trigonometric relation:

3\cdot \cos \alpha = AB - 4\cdot \cos 73^{\circ}

3\cdot \sin \alpha = 4\cdot \sin 73^{\circ} - 3

9\cdot \cos^{2}\alpha + 9\cdot \sin^{2}\alpha =(AB-4\cdot \cos 73^{\circ})^{2}+(4\cdot \sin 73^{\circ}-3)^{2}

9 = AB^{2}-2.339\cdot AB + 1.368 + 0.681

The following second-order polynomial is presented below:

AB^{2}-2.339\cdot AB -6.951 = 0

Roots of the polynomial are described hereafter:

AB_{1} \approx 4.054 and AB_{2} \approx -1.715

Only the first root is reasonable, as length is a positive variable. The length is AB \approx 4.054.

6 0
3 years ago
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