The probability that a randomly selected score is greater than 334 will be 0.02275.
<h3>What is a normal distribution?</h3>
The Gaussian Distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The GRE is an entrance exam that many students are required to take in order to apply to graduate school. In 2014, the combined scores for the Verbal and Quantitative sections were approximately normally distributed with a mean of 310 and a standard deviation of 12.
Then the probability that a randomly selected score is greater than 334 will be
The z-score is given as
z = (x - μ)/σ
z = (334 - 310)/12
z = 24/12
z = 2
Then the probability will be
P(x > 334) = P(z > 2)
P(x > 334) = 1 - P(x<334)
P(x > 334) = 1 - 0.97725
P(x > 334) = 0.02275
More about the normal distribution link is given below.
brainly.com/question/12421652
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Step-by-step explanation:
=2b+9
=2×3+9
=6+9
=15
hope it helps.
Answer: the answer is c, the # 2 is prime but the product of 2 * 2 = 4
and 4 isn't odd
Step-by-step explanation:
Answer:
35 glasses of classic milk tea
15 glasses of flavored milk tea
Step-by-step explanation:
You sold 50 glasses of classic and flavored milk tea.
c + f = 50
You made 4700 when classic tea costs 100 and flavored tea costs 80.
100c + 80f = 4700
Use this system of equation to solve. Use substitution. Rearrange the first equation so that it is equal to c. Then, plug the c-value into the second equation.
c + f = 50
c = 50 - f
100c + 80f = 4700
100(50 - f) + 80f = 4700
5000 - 100f + 80f = 4700
5000 - 20f = 4700
-20f = -300
f = 15
Plug the f-value into one of the equations and solve for c.
c + f = 50
c + 15 = 50
c = 35
35 glasses of classic milk tea and 15 glasses of flavored milk tea were sold.