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Law Incorporation [45]
3 years ago
9

If l║m and m∠8 = 109°, what is m∠5?

Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0

you need to see all the measurements to know what m∠5 to get the answer.

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Choose the fraction that goes in the blank. 5/12< _____<3/4
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All of the following fractions work: 1/2, 7/12, 8/12. There are endless possibilities.

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What is the y- intercept for -3x+5y=15
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Rochelle and her father watched a football game on monday night the quarterback threw the all a total of 318 yards how many feet
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Answer:

954 feet.

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We have been given that the quarterback threw the ball a total of 318 yards. We are asked to find the number of feet the quarter back throw the ball.

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318\text{ yards}\times \frac{\text{3 feet}}{\text{Yard}}=318\times\text{3 feet}=954\text{ feet}

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3 years ago
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

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