Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
Answer:
(x, y) = (3, 1)
Step-by-step explanation:
given the 2 equations
2x + 3y = 9 → (1)
x + 5y = 8 → (2)
multiplying (2) by - 2 then adding to (1) will eliminate the term in x
multiply (2) by - 2
- 2x - 10y = - 16 → (3)
add 1(1) and (3) term by term
(2x - 2x) + (3y - 10y) = (9 - 16)
- 7y = - 7 ( divide both sides by - 7 )
y = 1
Substitute y = 1 in either (1) or (2) and solve for x
(1) : 2x + 3 = 9 ( subtract 3 from both sides )
2x = 6 ( divide both sides by 2 )
x = 3
Solution is (3, 1 )
log(4) + log(2) - log(5)
= log(2²) + log(2) - log(5)
= 2 log(2) + log(2) - log(5)
= 3 log(2) - log(5)
= log(2³) - log(5)
= log (2³/5)
= log (8/5)
= log (1.6) = 0.2041... (rounded)
Answer:-3
Step-by-step explanation:
