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3 years ago

In analyzing a line graph, why is slope important?

Mathematics

2 answers:

alina1380 [7]3 years ago

7 0

Answer:

The slope of the line reflects the actual d.

Dmitriy789 [7]3 years ago

6 0

What the other dude said

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According to a survey, 65% of murders committed last year were cleared by arrest or exceptional means. Fifty murders committed

monitta

Answer:

a) $P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421$

b) $P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714$

$P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502$

$P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319$

And adding these values we got:

$P(36 \leq X \leq 38)= 0.1535$

c) We can find the expected value given by:

$E(X) = np =50*0.65 = 32.5$

And the standard deviation would be:

$\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373$

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

$\mu -2\sigma = 32.5- 2*3.373 = 25.75$

And then we can consider a value of 18 as unusual lower for this case.

Step-by-step explanation:

Let X the random variable of interest "number cleared by arrest or exceptional", on this case we can model this variable with this distribution:

$X \sim Binom(n=50, p=0.65)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want this probability:

$P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421$

Part b

We want this probability:

$P(36 \leq X \leq 38)$

We can find the individual probabilities:

$P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714$

$P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502$

$P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319$

And adding these values we got:

$P(36 \leq X \leq 38)= 0.1535$

Part c

We can find the expected value given by:

$E(X) = np =50*0.65 = 32.5$

And the standard deviation would be:

$\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373$

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

$\mu -2\sigma = 32.5- 2*3.373 = 25.75$

And then we can consider a value of 18 as unusual lower for this case.

6 0

3 years ago

A multiple-choice test consists of 10 questions. Each question has answer choices of a ,b c, d ,e , and , and only one of the ch

aalyn [17]

Its easier to find the complement of that instead
so you find the probability of 1 and 0
The .2 in the answer is the probability of each question 1/5
(10 C 0) x .2^0 (1-.2)^10-0=.1074
(10 C 1) x .2^1 (1-.2)^10-1=.2684
.2684+.1074=.3758 and that's the complement
so 1 - .3758= .6242
I too have a stats exam on this tomorrow lol

4 0

3 years ago

2x+5 is greater than 50

katrin2010 [14]

2x+5=50
-5 -5
—————-
2x = 45
Divide by 2
45/2 = 22.5
I hope this makes sense

6 0

3 years ago

Read 2 more answers

Ronald brought a jacket on Friday that had original price if $45. It was on sale at 10% off its original price. Which formula sh

trapecia [35]

The answer is D 1.1(45-45(.7))

3 0

2 years ago

The cost c, to produce b baseball bats per day is modeled by the function c(b)=0.06b^2 - 7.2b + 390. What number of bats should

Finger [1]

You have two choices.
The minimum possible cost to operate your bat factory for a day is $390,
and there are two quantities of bats that both cost that much.

One possibility:
   Produce no bats at all per day. Zero. Nada. None.
   Cost = 0.06(0)² - 7.2(0) + 390 = $390 per day.

The other choice:
   Produce 120 bats per day.
   Cost = 0.06(120²) - 7.2(120) + 390
      = 0.06(14,400) - 7.2(120) + 390
= 864 - 864 + 390
= $390 per day.

If you produce any other number of bats in a day ... more than zero
but not 120 ... then it will cost you more than $390 to operate the factory
that day.

8 0

3 years ago