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mote1985 [20]
3 years ago
6

Complete the square for a circle. For #42.

Mathematics
1 answer:
makkiz [27]3 years ago
8 0

we are given

2x^2+2y^2-28x+20y+20=0

we can see that

each terms are multiple of 2

so, we can factor out 2

2(x^2+y^2-14x+10y+10)=0

we can divide both sides by 2

x^2+y^2-14x+10y+10=0

we can rearrange it

x^2+-14x+y^2+10y+10=0

now, we can move 10 on right side

x^2+-14x+y^2+10y=-10

x^2+-2*7*x+y^2+2*5*y=-10

now, we can add both sides 7^2 and 5^2

x^2+-2*7*x+7^2+y^2+2*5*y+5^2=-10+7^2+5^2

(x-7)^2+(y+5)^2=-10+7^2+5^2

we can simplify it

(x-7)^2+(y+5)^2=64

we can also write as

(x-7)^2+(y+5)^2=8^2..............Answer

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