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tiny-mole [99]
3 years ago
15

Help with math immidiatly

Mathematics
1 answer:
german3 years ago
5 0
3. 134
x 11
_____
134
+1340
_____
1,474


4. 208
x 26
_____
1,248
+4160
_____
5,408


5. 428
x 35
_____
2,140
+13,840
______
14,980


6. 275
x 56
_____
1,650
+13,750
______
15,400

I’m not sure if I’m too late or not but have a good day!!
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In finding the solution of the equation 5 - 3x = 2x + 9, 3x is added to both sides of the equation first. Which of the following
KIM [24]

Answer:

C should be next

Step-by-step explanation:

Ok after you add 3x to both side you should get this:

5=5x+9

It makes since o subtract 9 from both sides at least for me.

Hope this helps :D

5 0
3 years ago
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What is the volume of a cube if one side is 2x
Anarel [89]

Answer:

8x^3

you are welcome

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You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
navik [9.2K]

Answer:

1) yes ; 2) 1/36 ; 3) 1/36 ; 4) 1/18

Step-by-step explanation:

Given the following :

Two fair dice : 1 green ; 1 red

A) Are the outcomes on the dice independent:

Yes, becomes the outcome of the green dice does not have any effect on the outcome of the red dice.

B) Find P(1 on green die and 5 on red die).

Probability = (number of required outcome) / (total possible outcomes)

Total outcomes of a dice = 6

P(1 on green) = 1 / 6

P(5 on red) = 1/6

P(1 on green die and 5 on red die) :

(1/ 6) × (1/6) = 1/36

C) Find P(5 on green die and 1 on red die)

P(5 on green) = 1/6

P(1 on red) = 1/6

Find P(5 on green die and 1 on red die):

1/6 × 1/6 = 1/36

D) Find P((1 on green die and 5 on red die) or (5 on green die and 1 on red die))

P(5 on green die and 1 on red die) = 1/36

P(1 on green die and 5 on red die) = 1/36

P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) =

P(5 on green die and 1 on red die) + P(1 on green die and 5 on red die)

= (1/36 + 1/36) = 2 /36 = 1/18

8 0
3 years ago
The volume of
algol [13]
1/10 of an ounce is the answer

8 0
4 years ago
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Two semicircles are attached to the sides of a rectangle as shown.
melomori [17]

Answer:

157\ in^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

A=14*5=70\ in^{2}

<u>The area of the small semicircle is equal to</u>

A=\pi r^{2} /2

r=5/2=2.5\ in -----> radius is half the diameter

substitute

A=(3.14)(2.5^{2})/2=9.8125 in^{2}

<u>The area of the larger semicircle is equal to</u>

A=\pi r^{2} /2

r=14/2=7\ in -----> radius is half the diameter

substitute

A=(3.14)(7^{2})/2=76.93\ in^{2}

The area of the figure is equal to

70+9.8125+76.93=156.7425=157\ in^{2}

8 0
3 years ago
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