Which shows the list below in order from greatest to least. 3.4848, -3 19/20, √11, -3.58, 362%
1 answer:
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Answer:
135 and 135
Step-by-step explanation:
The computation is shown below:
The number of examiners who passed in only one subject is as follows
= n(E) - n(E ∩M) + n(M) - n(E ∩M)
= (80 - 60 + 70 - 60)%
= 30%
Now the number of students who passed in minimum one subject is
n(E∪M) = n(E) + n(M) - n(E ∩M)
= 80 - + 70 - 60
= 90%
Now the number of students who failed in both subjects is
= 100 - 90%
= 10% of total students
= 45
So total number of students appeared for this 450
So, those who passed only one subject is
= 450 × 30%
= 135
Now the Number of students who failed in mathematics is
= 100% - Passed in Mathematics
= 100% - 70%
= 30% of 450
= 135
Answer:
Step-by-step explanation:
<u>Step 1</u>:-
Suppose that E and F are two events and that P(E n F) = 0.3
also given P(E) =0.5
<u>Conditional probability</u>:-
if E₁ and E₂ are two events in a Sample S and P(E₁)≠ 0, then the probability of E₂ , after the event E₁ has occurred, is called the <u>Conditional probability</u>
of the event E₂ given E₁ and is denoted by