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Tanya [424]
3 years ago
11

Suppose you have $10,000 to invest. Which investment yields the greater return over 7 years: 6.6% compounded monthly or 6.7% com

pounded quarterly? A) Both investment plans yield the same return. B) $10,000 invested at 6.6% compounded monthly over 7 years yields the greater return. C) $10,000 invested at 6.7% compounded quarterly over 7 years yields the greater return.
Mathematics
1 answer:
joja [24]3 years ago
8 0

Answer:

C) $10,000 invested at 6.7% compounded quarterly over 7 years yields the greater return.

Step-by-step explanation:

-We determine the effective interest rate in both scenarios and use it to calculate the investment's value after 7 years.

#Given n=7yrs, P=$10,000 and i=6.6% compounded monthly:

i_m=(1+i/m)^m-1\\\\=(1+0.066/12)^{12}-1=0.06803\\\\\therefore A=P(1+i_m)^n\\\\=10000(1.06803)^7\\\\\approx \$15,852.00

#Given n=7rs, P=10000, i=6.7%

i_m=(1+i/m)^m-1\\\\=(1+0.067/4)^{4}-1=0.06870\\\\\therefore A=P(1+i_m)^n\\\\=10000(1.06870)^7\\\\\approx \$15,921.75

Hence, the investment has the largest value($15,921.75) when the interest rate is compounded quarterly.

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Is 4/6 and 6/12 equivalent
larisa86 [58]
4/6
= (4/2) / (6/2)
= 2/3

6/12
= (6/6) / (12/6)
= 1/2

Because 2/3 ≠ 1/2, 4/6 and 6/12 are NOT equivalent.
3 0
3 years ago
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Given the definitions of f (x) and g(x) below, find the value of (g • f)(9).
Stells [14]

9514 1404 393

Answer:

  (g·f)(9) = 496

Step-by-step explanation:

One way to do this is to find the values of g(9) and f(9).

  g(9) = (3x -1)x +14 = (3(9) -1)(9) +14 = 26(9) +14 = 248

  f(9) = -(9) +11 = 2

Then ...

  (g·f)(9) = g(9)·f(9) = 248·2

  (g·f)(9) = 496

8 0
3 years ago
Solve the system by substitution.<br> y = 3x + 28<br> y = -4x
Mazyrski [523]

Answer:

(-4, 16)

Step-by-step explanation:

3 0
3 years ago
Write a description of how a diagram can help you solve 2×40
olya-2409 [2.1K]
Draw 40 boxes, and in a separate section draw another 40 boxes.
(If you have the time :) )
8 0
3 years ago
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PLEASE HELP!!!!!
Zielflug [23.3K]
Question #1

Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.

Part B:
\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}
The slope is 22.

Part C:
y = mx + b
y = 22x + 5

We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10

The domain is 10.



Question #2

Part A:

(2,255)
(5,480)

Standard form is Ax + By = C

\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}

Let's plug this into this form first:
y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55

Now, let's make it into Standard Form.
y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}
What, which is in the box, is your final answer. :)

Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
\boxed{f(x) = 85x + 55}

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
5 0
3 years ago
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