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2 years ago

The number of cars at a dealership dropped from 64 to 48 after a weekend sale.

Mathematics

1 answer:

tigry1 [53]2 years ago

8 0

Answer: B. 25%

Step-by-step explanation:

64-48 = 16

16/ 64= 0.25

0.25 x 100 = 25%

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Solve. Round to the nearest tenth. 6 2-12 19 2x-2 HELP ASAP!!

Strike441 [17]

Answer:

$\displaystyle x = \frac{216}{7}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{6}{19} = \frac{x - 12}{2x - 2}$

Step 2: Solve for x

Cross-multiply: $\displaystyle 6(2x - 2) = 19(x - 12)$
Distribute: $\displaystyle 12x - 12 = 19x - 228$
Isolate x terms: $\displaystyle -12 = 7x - 228$
Isolate x term: $\displaystyle 216 = 7x$
Isolate x: $\displaystyle \frac{216}{7} = x$
Rewrite: $\displaystyle x = \frac{216}{7}$

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Step-by-step explanation:

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2 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

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2 years ago