Explanation:
calculators work by processing information in binary form. We're used to thinking of numbers in our normal base-ten system, in which there are ten digits to work with: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. The binary number system is a base-two system, which means there are only two digits to work with: 0 and 1. Thus, when you input numbers into a calculator, the integrated circuit converts those numbers to binary strings of 0s and 1s.
The integrated circuits then use those strings of 0s and 1s to turn transistors on and off with electricity to perform the desired calculations. Since there are only two options in a binary system (0 or 1), these can easily be represented by turning transistors on and off, since on and off easily represent the binary option
Once a calculation has been completed, the answer in binary form is then converted back to our normal base-ten system and displayed on the calculator's display screen.
To accomplish this without using a loop,
we can use math on a string.
Example:
print("apple" * 8)
Output:
appleappleappleappleappleappleappleapple
In this example,
the multiplication by 8 actually creates 8 copies of the string.
So that's the type of logic we want to apply to our problem.
<span>def powersOfTwo(number):
if number >= 0:
return print("*" * 2**number)
else:
<span>return
Hmm I can't make indentations in this box,
so it's doesn't format correctly.
Hopefully you get the idea though.
We're taking the string containing an asterisk and copying it 2^(number) times.
Beyond that you will need to call the function below.
Test it with some different values.
powersOfTwo(4) should print 2^4 asterisks: ****************</span></span>
Answer:blue is the best color choice for a global audience.
