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Anestetic [448]

3 years ago

8

Yolo has 2 pieces of string. One is 32 inches long, the other is 48 inches long. She wants to make as many necklaces as she can,

all of the same length. What is the longest necklace that can be made?

2 answers:

alexandr402 [8]3 years ago

4 0

She can make a necklace 80 inches long

Arte-miy333 [17]3 years ago

3 0

The Greatest Common Factor of 32 and 48 is 16.

The longest necklace she can make is of 16 inches length.

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Joseph and Sanjay are trying to finish their math homework before their favorite TV show starts. Joseph finishes 2/3 of his prob

kicyunya [14]

The correct answer is Sanjay! :)

Explanation:
Joseph: 2/3
Sanjay: 5/7
2/3 and 5/7
14/21 and 15/21
Therefore, Sanjay is the answer.

5 0

2 years ago

If a school cafeteria needs c cans of soup each week for each student, and if there are s students in the school, for how many w

Sphinxa [80]

Answer:

x/(cs)

Step-by-step explanation:

Let w represent the number of weeks we're feeding students soup.

$w\,\text{weeks}\times\dfrac{c\,\text{cans}}{\text{student}\cdot\text{week}}\times s\,\text{students}=x\,\text{cans}\\\\w=\dfrac{x}{c\cdot s}\qquad\text{divide by $c\cdot s$}$

4 0

3 years ago

Read 2 more answers

The doubling period of a bacterial population is 20 20 minutes. At time t = 100 t=100 minutes, the bacterial population was 9000

Nuetrik [128]

Answer:

The initial population was 2810

The bacterial population after 5 hours will be 92335548

Step-by-step explanation:

The bacterial population growth formula is:

$P = P_0 \times e^{rt}$

where P is the population after time t, $P_0$ is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours

Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:

$2 P_0 = P_0 \times e^{r 1/3}$

$2 = e^{r \; 1/3}$

$ln 2 = r \; 1/3$

$ln 2 \times 3 = r$

$2.08 \% = r$

Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:

$90000 = P_0 \times e^{2.08 \; 5/3}$

$\frac{9000}{e^{2.08 \; 5/3}} = P_0$

$2810 = P_0$

Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

$P = 2810 \times e^{2.08 \; 5}$

$P = 92335548$

3 0

3 years ago

38 4/7% as a fraction

Lelu [443]

38 4/7 = 270/7

% (percent) means per hundred (1/100)

so, (270/7)% is same thing as 270/700 or 27/70.

Answer: 270/100 or 27/70

3 0

3 years ago

The half-life of Carbon-14 is 5730 years. Suppose a fossil is found with 50% of Carbon-14 as compared to a living sample. How ol

melisa1 [442]

The answer is C. Because it takes 5730 years for half of a sample of carbon-14 atoms to decay. It says that 50% of the carbon atoms have decayed so that means that 5730 years have elapsed for that fossil.

I hope that helps.

4 0

2 years ago