The value of "x" is 5.
![\large\underline{\sf{Solution-}}](https://tex.z-dn.net/?f=%5Clarge%5Cunderline%7B%5Csf%7BSolution-%7D%7D)
Given that,
A trapezium ABCD in which AB || CD such that
Now,
![\rm In \: \triangle \: AOB \: and \: \triangle \: COD](https://tex.z-dn.net/?f=%5Crm%20In%20%5C%3A%20%5Ctriangle%20%20%5C%3A%20AOB%20%20%5C%3A%20and%20%5C%3A%20%5Ctriangle%20%5C%3A%20%20COD)
![\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}](https://tex.z-dn.net/?f=%5Crm%20%20%5C%3A%20%5Cangle%20%20%5C%3A%20AOB%20%20%5C%3A%20and%20%5C%3A%20%5Cangle%20%5C%3A%20%20COD%20%5C%3A%20%20%5C%3A%20%20%5C%7Bvertically%20%5C%3A%20opposite%20%5C%3A%20angles%20%5C%7D)
![\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}](https://tex.z-dn.net/?f=%5Crm%20%20%5C%3A%20%5Cangle%20%20%5C%3AABO%20%20%5C%3A%20and%20%5C%3A%20%5Cangle%20%5C%3A%20%20CDO%20%5C%3A%20%20%5C%3A%20%20%5C%7Balternate%20%5C%3A%20interior%20%5C%3A%20angles%20%5C%7D)
![\bf \: \triangle \: AOB \: \sim \: \triangle \: COD \: \: \: \{AA \: similarity \}](https://tex.z-dn.net/?f=%5Cbf%20%5C%3A%20%5Ctriangle%20%20%5C%3A%20AOB%20%5C%3A%20%20%5Csim%20%5C%3A%20%20%5Ctriangle%20%20%5C%3A%20COD%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%7BAA%20%5C%3A%20similarity%20%5C%7D)
![\bf\longmapsto\:\dfrac{AO}{CO} = \dfrac{BO}{DO}](https://tex.z-dn.net/?f=%5Cbf%5Clongmapsto%5C%3A%5Cdfrac%7BAO%7D%7BCO%7D%20%20%3D%20%5Cdfrac%7BBO%7D%7BDO%7D%20)
![\rm \longmapsto\:\dfrac{x - 1}{x + 1} = \dfrac{x + 1}{x + 4}](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%5Cdfrac%7Bx%20-%201%7D%7Bx%20%2B%201%7D%20%20%3D%20%5Cdfrac%7Bx%20%2B%201%7D%7Bx%20%2B%204%7D%20)
![\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%28x%20-%201%29%28x%20%2B%204%29%20%3D%20%20%7B%28x%20%2B%201%29%7D%5E%7B2%7D%20)
![\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%20%7Bx%7D%5E%7B2%7D%20-%20x%20%2B%204x%20-%204%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%2B%201%20%2B%202x)
![\rm \longmapsto\: 3x - 4 = 1 + 2x](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%203x%20-%204%20%3D%20%201%20%2B%202x)
![\rm \longmapsto\: 3x - 2x= 1 +4](https://tex.z-dn.net/?f=%5Crm%20%5Clongmapsto%5C%3A%203x%20%20-%20%202x%3D%20%201%20%2B4)
![\bf\longmapsto \:x = 5](https://tex.z-dn.net/?f=%5Cbf%5Clongmapsto%20%5C%3Ax%20%3D%205)
The 3rd option is correct
Answer:
30 students are in the science class and 3 students recieved a failing grade.
Answer:
Step-by-step explanation:
a) the points (0,60) and (6.0) are the intercept points for the graph of the car slowing down ( accelerating in the opposite direction than it's traveling)
we already know the slope of the line b/c that the rate at which it's slowing .. -10 =m which is the slope of the line .. down 10
use the point-slope formula y-y1 = m(x-x1) and plug in either given point for (x1,y1)
b) y -60 = -10(x-0)
y= -10x+60
thats the slope-intercept form of the equation