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3 years ago

Please answer quickly

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

3 0

Answer:

YZ = 18

Step-by-step explanation:

XY = YZ because the line indicates they are the same length

XY = 18 so YZ = 18

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Need answer thanks! only answer if you know please!

Vaselesa [24]

Answer:

a) $k \approx 0.0602\,\frac{1}{min}$ ( $k\approx 6.02\,\frac{\%}{min}$ ), b) $k \approx 0.0648\,\frac{1}{min}$ ( $k \approx 6.48\,\frac{\%}{min}$ ), c) $t_{1/2} \approx 60.274\,days$ , d) $t_{1/2}\approx 4.305\,min$ , e) $k \approx 0.3\,\frac{1}{min}$ ( $k\approx 30\,\frac{\%}{min}$ ), f) $k \approx 0.0120\,\frac{1}{min}$ ( $k \approx 1.20\,\frac{\%}{min}$ ), g) $k \approx 2.876\times 10^{-5}\,\frac{1}{yr}$ ( $k \approx 2.876\times 10^{-3}\,\frac{\%}{yr}$ )

Step-by-step explanation:

All radioactive isotopes decay exponentially, the mass of the isotope as a function of time ( $m(t)$ ), measured in grams, is defined by:

$m(t) = m_{o}\cdot e^{-k\cdot t}$ (1)

Where:

$m_{o}$ - Initial mass of the isotope, measured in grams.

$k$ - Decay rate, measured in $\frac{1}{min}$ or $\frac{1}{day}$ or $\frac{1}{yr}$ .

$t$ - Time, measured in minutes, days or years.

We define the decay rate in terms of half-life by using the following expression:

$k = \frac{\ln 2}{t_{1/2}}$ (2)

Where $t_{1/2}$ is the half-life of the isotope, measured in minutes or years.

Now we proceed to determine the missing values:

a) Polonium-200 ( $t_{1/2} = 11.5\,min$ )

$k = \frac{\ln 2}{11.5\,min}$

$k \approx 0.0602\,\frac{1}{min}$

b) Lead-194 ( $t_{1/2} = 10.7\,min$ )

$k = \frac{\ln 2}{10.7\,min}$

$k \approx 0.0648\,\frac{1}{min}$

c) Iodine-125 ( $k = 0.0115\,\frac{1}{day}$ )

$t_{1/2} = \frac{\ln 2}{k}$

$t_{1/2} = \frac{\ln 2}{0.0115\,\frac{1}{day} }$

$t_{1/2} \approx 60.274\,days$

d) Kryption-75 ( $k = 0.161\,\frac{1}{min}$ )

$t_{1/2} = \frac{\ln 2}{k}$

$t_{1/2} = \frac{\ln 2}{0.161\,\frac{1}{min} }$

$t_{1/2}\approx 4.305\,min$

e) Strontium-79 ( $t_{1/2} = 2.3\,min$ )

$k = \frac{\ln 2}{2.3\,min}$

$k \approx 0.3\,\frac{1}{min}$

f) Uranium-229 ( $t_{1/2} = 58\,min$ )

$k = \frac{\ln 2}{58\,min}$

$k \approx 0.0120\,\frac{1}{min}$

g) Plutonium-239 ( $t_{1/2} = 24100\,yr$ )

$k = \frac{\ln 2}{24100\,yr}$

$k \approx 2.876\times 10^{-5}\,\frac{1}{yr}$

6 0

3 years ago

8x + 3y = 4 - 7x + 5y = -34

maxonik [38]

Answer:

The solution is in the picture above

3 0

4 years ago

Plzzz help will give brainlist! Thank you in advance!

erastova [34]

Answer:

dont click the link!!

Step-by-step explanation:

5 0

3 years ago

I will mark the correct answer as brainliest! A piece of fabric 180 inches long is cut in 2 pieces such that 3 times the larger

Ulleksa [173]

Let one piece be x inches long then the other piece is 180-x inches long.

3x > 4 (180-x)
3x > 720 - 4x
7x > 720

x > 103 6/7 ins

the 2 pieces could be 107 inches and 180-107 = 73 inches

5 0

3 years ago

Is 74 inches greater or less than 2 yards 2 inches?

Effectus [21]

They are equivalent:
74 inches=74 inches
2 yards, 2 inches= 74 inches

2 yards>6 feet>72 inches+2 inches>74 inches
OR
1 yard=36 inches>2 yards=72 inches+2 inches>74 inches

Hope this helps!

8 0

4 years ago

Read 2 more answers