Answers:
After 7 years the car is worth $10,196(,46)
Explanation:
Year 1: $24,950•0,88=21,956
Year 2: $21,956•0,88=19,321(,28)
Year 3: $19,321(,28) •0,88=17,002(,73)
Year 4: $17,002(,73) •0,88=14,962(,40)
Year 5: $14,962(,40) •0,88=13,166(,91)
Year 6: $13,166(,91) •0,88=11,586(,88)
Year 7: $11,586(,88) •0,88=10,196(,46)
The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
brainly.com/question/1130127
Answer: Division of Polynomials is just like the long division that most of us despise but this division is with Variables
Step-by-step explanation:
Example
With whatever equation you have you will
- First: set up the division putting the dividend inside the divisor outside and to the left
- Second: Ignore everything past the leading terms and just focus on the leading _ of the divisor and the leading _ of the dividend (just like in regular long division.
- Thirdly: Take whatever is on top and multiply is by the divisor {What is on the side} carry the result underneath put it exactly below the number from the dividend
- Fourth: Multiply the number that is on top by the number that is on the side, carry what is on the side underneath putting it below the other dividend.
- Fifth: Do the subtraction
- Sixth To subtract change all the signs in the second line, then add down.
- Next: Carry down that last term from the dividend
- From there you multiply and then add down again and you should be left with the answer....
If this was to many words let me know and I will upload a picture and explain with a real equation.
According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:
Here, n is equal to 66 and by substituting the value to the equation we get:
k = 7.0444
k ≈ 7
Learn more about Sturge's rule here: brainly.com/question/28184369
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Answer:
<em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>
Step-by-step explanation:
<u>f</u><u>{</u><u>5</u><u>}</u> = <u>6</u><u>(</u><u>5</u><u>^</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>2</u><u>(</u><u>5</u><u>)</u><u> </u><u>-</u><u> </u><u>7</u>
g{-3}= 4(-3)-3
= <u>6</u><u>(</u><u>2</u><u>5</u><u>)</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>
-12 - 3
= <u>150</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>
- 15
= <u>1</u><u>5</u><u>3</u>
-15
= <u>-</u><u>5</u><u>1</u>
5
= <em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>