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3 years ago

John has 15 t shirts. 6 black, 3 red, 2 purple, 2 dark blue, 1 light blue, 1 purple

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

What is the equation you are supposed to solve for

Troyanec [42]3 years ago

3 0

Answer:

ok.... what is the question here....?? ;-;

Step-by-step explanation:

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What is the value of x in the equation 3(4x-1)-3x=5-(x-8)?

Setler [38]

12x-3-3x=5-(x-8)
9x-3=5-(x-8)
9x-3=5-x+ 8
9x-3=13-x
9x=16- x
10x=16
X= 8/5

4 0

2 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

2 years ago

60 Points !!!!!

zheka24 [161]

Answer:

A yes ; it can be rotated 360° or less and match the original figure

8 0

2 years ago

2) Two big bags of sugar plus one small bag of flour add up to a total of 12 kg.

alisha [4.7K]

Answer:

It's just a simultaneous equation

Step-by-step explanation:

Let a big bag of sugar = x

Let a small bag of flour = y

x+x+y = 12kg

2x+y = 12kg ... 1

x-y = 2kg ... 2

Add 1 and 2

2x+y = 12

x -y = 2

3x = 14

x = 14/3 = 4.66

Substitute value of x into 1

2(4.66)+y = 12

9.333 + y = 12

12 - 9.333= 12

y = 2.66

Hope you understand it

And I hope my answer was of help to you.

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=25%283x%20-%20y%29%20%5E%7B2%7D%20%20-%2016%285x%20%2B%203y%29%20%5E%7B2%7D%20%20%3D%20%20" id

Arlecino [84]

25(3x-y)²-16(5x+3y)²=25(9x²-6xy+y²)-16(25x²+30xy+9y²)=

=225x²-15xy+25y²-400x²-480xy-144y²=-175x²-630xy-119y²

3 0

2 years ago

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