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3 years ago

Zero Product Property Help asap (n-5)(n+3)=0

Mathematics

1 answer:

Karolina [17]3 years ago

3 0

(n-5)(n+3)=0
n^2 -2n-15=0
a = 1, b = -2, c = -15
(-2)^2-4x1x(-15)
= 64
so 64 is your answer:)

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Hi there!

»»————-　★　————-««

I believe your answer is:

(4, 1)

»»————-　★　————-««

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~Solve by Graphing~

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⸻⸻⸻⸻

»»————-　★　————-««

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Brilliant_brown [7]

Answer:

$f(x)=\sqrt{x-1}$ -----> Graph C

$f(x)=\sqrt{x}$ -----> Graph A

$f(x)=\sqrt{x}-1$ -----> Graph B

$f(x)=-\sqrt{x}$ -----> Graph D

$f(x)=-\sqrt{x-1}$ -----> Graph E

Step-by-step explanation:

we have

case a) $f(x)=\sqrt{x-1}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x-1\geq 0$

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The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval -----> [0,∞)

All real numbers greater than or equal to 0

case b) $f(x)=\sqrt{x}$

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we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> [0,∞)

All real numbers greater than or equal to 0

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The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

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case d) $f(x)=-\sqrt{x}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> (-∞,0]

All real numbers less than or equal to 0

case e) $f(x)=-\sqrt{x-1}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x-1\geq 0$

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The domain is the interval -----> [1,∞)

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3 years ago