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ale4655 [162]
3 years ago
10

Write a quadratic function in standard form whose graph passes through (-11,0), (1,0), and (-3,64).

Mathematics
1 answer:
densk [106]3 years ago
6 0

Answer: (-2,25)

Step-by-step explanation:

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An observer (O) spots a plane flying at a 55° angle to his horizontal line of sight. If the plane is flying at an altitude of 21
xz_007 [3.2K]

Answer:

<em>B. 25,636 feet</em>

Step-by-step explanation:

sin(55) = h/x

h = 21,000

sin(55) = 21,000/x

x = 21,000/sin(55)

x = 25636.27 ≈ 25,636 feet

Hope this helped! :)

3 0
3 years ago
Read 2 more answers
Use the method of completing the square to transform the quadratic equation into the equation form (x – p)2 = q.
oee [108]
X^2-12x-9=0
Add 9 to both sides
x^2-12x=9
Add (b/2)^2 to both sides
x^2-12x+36=45
Factor
(x-6)^2=45
So C is the answer
8 0
4 years ago
Question
mixas84 [53]
First you multiply 5*5 which is 25 and then you multiply 25*12 which is 300 and 300*14 is 4,200.so your answer is 4,200
7 0
3 years ago
In March, you have $220 in your savings account. By the end of April, your savings have increased by 30%. How much money do you
Lana71 [14]

Answer:

$286

Step-by-step explanation:

220:100=2.2

2.2 x 30 = 66

220+66=286

6 0
3 years ago
How many Solutions does this system have? (1 point)
mixas84 [53]

The given system of equation that is 2x+y=3 and 6x=9-3y has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}

Let us first bring the equation in standard form for comparison

\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}

To check how many solutions are there for system of equations a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0, we need to compare ratios of \frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}

In our case,  

a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3

a_{2}  = 6, b_{2} = 3,\text{ and }c_{2} = -9

\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}

As \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}, so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0
3 years ago
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