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3 years ago

Write a quadratic function in standard form whose graph passes through (-11,0), (1,0), and (-3,64).

Mathematics

1 answer:

densk [106]3 years ago

6 0

Answer: (-2,25)

Step-by-step explanation:

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2 years ago

If you shift the quadratic parent function, f(x)=x2 , right 10 units, what is the equation of the new function?

tiny-mole [99]

Answer:

Step-by-step explanation:

The standard form of a quadratic is

$y=a(x-h)^2+k$ where h is side to side movement (it's also the x coordinate of the vertex) and k is the up or down movement (it's also the y coordinate of the vertex). If there is no up or down movement, the k value is 0. (We don't need to worry about the value for a here; it's 1 but that doesn't change anything for us in our problem). Movement to the right is positive, so we are moving +10. Filling that into our equation:

$y=(x-(+10))^2$ and simplified:

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3 years ago

Given that Segment BE is 5 units, find the indicated measures for each

zalisa [80]

Answer:

The indicated measure of the length of AE = 5 units

Step-by-step explanation:

To determine:

What is the indicated measure of length?

Information Fetching and Solution Steps:

From this single diagram, it seems the indicated measure of length which we have to determine is the length of AE.

Given that Segment BE is 5 units. i.e. BE = 5 units

As the square has two equal diagonals AC and DB which meet at point E.

So, point E being the common mid-point of both diagonals.

As both of the diagonals of square are equal in length.

And the length of BE is 5 units, which is half the length of BD. It means the diagonal BD has a length of 10 units.

And since both diagonals AC and DB are equal in length, it means the length of AC must be 10 units.

Since, AC has the length of 10 units, it means the length of AE must be half of the length of AC. Thus, the indicated measure of the length of AE is 5 units.

Therefore, the indicated measure of the length of AE = 5 units

Keywords: square, diagonals, length, line segment

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3 years ago