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3 years ago

Will choose brainliest! Please help! (This is Khan Academy)

Mathematics

1 answer:

NeTakaya3 years ago

8 0

Answer:

Option B. A = (5/6)^-⅛

Step-by-step explanation:

From the question given above, we obtained:

(5/6)ˣ = A¯⁸ˣ

We can obtain the value of A as follow:

(5/6)ˣ = A¯⁸ˣ

Cancel x from both side

5/6 = A¯⁸

Recall:

M¯ⁿ = 1/Mⁿ

A¯⁸ = 1/A⁸

Thus,

5/6 = 1/A⁸

Cross multiply

5 × A⁸ = 6

Divide both side by 5

A⁸ = 6/5

Take the 8th root of both sides

A = ⁸√(6/5)

Recall

ⁿ√M = M^1/n

Thus,

⁸√(6/5) = (6/5)^⅛

Therefore,

A = (6/5)^⅛

Recall:

(A/B)ⁿ = (B/A)¯ⁿ

(6/5)^⅛ = (5/6)^-⅛

Therefore,

A = (5/6)^-⅛

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Factorise 2x^2 -x-21

yaroslaw [1]

Answer:

(x + 3) × (2x - 7)

Step-by-step explanation:

2x² - x - 21

Write as a difference

2x² + 6x - 7x - 21

Factor the expressions

2x × (x + 3) - 7 (x + 3)

Factor the expression

(x +3) × (2x - 7)

8 0

3 years ago

E = cos20º + cos40º + cos60º + … cos160º + cos180º

r-ruslan [8.4K]

Answer:

C) – 1

Step-by-step explanation:

E = cos20º + cos40º + cos60º +cos80° + cos 100°+cos120° +cos140° +cos160º + cos180º

E= 0.9 + 0.76 + 0.5+0.17+(-0.17)+(-0.5)+(-0.76) + ( – 0.9 ) + (– 1 )

E= 0.9 + 0.76 + 0.5 +0.17 - 0.17 - 0.5 -0.76 – 0.9 – 1

E= – 1

So ; equal – 1

I hope I helped you^_^

8 0

3 years ago

Rectangle 1 has length x and width y. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of K, where k

STALIN [3.7K]

$\bold{\huge{\underline{\pink{ Solution }}}}$

<h3>Given :- </h3>

Rectangle 1 has length x and width y
Rectangle 2 is made by multiplying each dimensions of rectangle 1 by a factor of k
Where, k > 0

<h3>Answer 1 :-</h3>

Yes, The rectangle 1 and rectangle 2 are similar .

<h3>According to the similarity theorem :-</h3>

If the ratio of length and breath of both the triangles are same then the given triangles are similar.

Let's Understand the above theorem :-

The dimensions of rectangle 1 are x and y

Now, 

Rectangle 2 is made by multiplying each dimensions of rectangle 1 by a factor of k .

Let assume the value of K be 5

Therefore, 

The dimensions of rectangle 2 are

$\sf{ 5x \:and \:5y }$

Now, The ratios of dimensions of both the rectangle :-

$\bold{Rectangle 1 = Rectangle 2}$

$\bold{\dfrac{ x }{y}}{\bold{ = }}{\bold{\dfrac{5x}{5y}}}$

$\bold{\blue{\dfrac{ x }{y}}}{\bold{\blue{ = }}}{\bold{\blue{\dfrac{x}{y}}}}$

From above, 

We can conclude that the ratios of both the rectangles are same

Hence , Both the rectangles are similar

<h3>Answer 2 :- </h3>

Here, 

We have to proof that, the

Perimeter of rectangle 2 = k(perimeter of rectangle 1 )

In the previous questions, we have assume the value of k = 5

<h3>Therefore, </h3>

According to the question,

Perimeter of rectangle 1

$\sf{ = 2( length + Breath) }$

$\bold{\pink{= 2( x + y ) }}$

Thus, The perimeter of rectangle 1

Perimeter of rectangle 2

$\sf{ = 2( length + Breath) }$

$\sf{ = 2(5x + 5y) }$

$\sf{ = 2 × 5( x + y) }$

$\bold{\pink{= 10(x + y) }}$

Thus, The perimeter of rectangle 2

According to the given condition :-

Perimeter of rectangle 2 = k( perimeter of rectangle 1 )

Subsitute the required values,

$\sf{ 2(x + y) = 10(x + y)}$

$\bold{\pink{2x + 2y = 5(2x + 2y) }}$

From Above, 

We can conclude that the, Perimeter of rectangle 2 is 5 times of perimeter of rectangle 1 and we assume the value of k = 5.

Hence, The perimeter of rectangle 2 is k times of rectangle 1

<h3>Answer 3 :</h3>

Here, 

We have to proof that ,

The area of rectangle 2 is k² times of the area of rectangle 1.

That is, 

Area of rectangle 1 = k²( Area of rectangle)

<h3>Therefore, </h3>

According to the question,

Area of rectangle 1

$\sf{ = Length × Breath }$

$\sf{ = x × y }$

$\bold{\red{= xy }}$

Area of rectangle 2

$\sf{ = Length × Breath }$

$\sf{ = 5x × 5y }$

$\bold{\red{ = 25xy }}$

According to the given condition :-

Area of rectangle 1 = k²( Area of rectangle)

$\sf{ xy = 25xy }$

$\bold{\red{xy = (5)²xy }}$

From Above, 

We can conclude that the, Area of rectangle 2 is (5)² times of area of rectangle 1 and we have assumed the value of k = 5

Hence, The Area of rectangle 2 is k times of rectangle 1 .

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2 years ago

Create another show real life multi-step function problems with Solutions in quadratics

artcher [175]

Answer:

Kazan also SOS jz zks zj sj aka always zks. aiwow

6 0

3 years ago

Can someone help me? I am struggling and I would be so happy if any of you helped me. Thank you for your help!

mash [69]

Answer:

Mean = 52

Standard Deviation = 13.64

Step-by-step explanation:

mean = 260/5

= 52

Standard Deviation = $\sqrt{\frac{930}{5} }$ = 13.64

I wasn't sure about my answer so used the Gauthmath app

8 0

3 years ago