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Mila [183]
3 years ago
15

Scientists released 5 foxes into a new habitat in year 0. Each year, there were

Mathematics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

f(x)= 5*4^x

Step-by-step explanation:

Since every year there are four times as many foxes as the year before, every year we need to multiply the previous population by 4. This leads to having to multiply by 4^{n}after n years have gone by. So we are in the presence of a population growth that goes as an exponential function of base "4".

A function f(x) that represents an exponential growth of such type can be written as:

f(x)= N_0 * 4^x

where x represents the variable time in years, 4 is the multiplicative base, and N_0 is what is defined as the "initial value" of the population (in our case 5 - for the 5 foxes initially released).

Notice also that when we start counting - time zero (x=0) the exponential form 4^0 = 1 becomes a one (1) and the expression reduces to this initial value  N_0 (5 in our case).

Therefore, the function representing this population growth is: f(x)= 5*4^x

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 Add 4x to each side, and get -3y=16+4x. Rearrange it to get it in the right order (y=mx+b).
This is -3y=4x+16. So the number in front of 'x' is 'm', which is the slope. You never actually see 'm', it is represented by a number. So four is the slope.
5 0
3 years ago
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In the year 2005, a total of 750 fish were introduced into a manmade lake. The fish population was expected to grow at a rate of
rewona [7]
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artcher [175]
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3 years ago
For what values of a are the following expressions true?/a+5/=-5-a
katovenus [111]

Explanation:

The expression is given below as

|a+5|=-5-a

Concept:

We will apply the bsolute rule below

\begin{gathered} if|u|=a,a>0 \\ then,u=a,u=-a \end{gathered}

By applying the concept, we will have

\begin{gathered} \lvert a+5\rvert=-5-a \\ a+5=-5-a,a+5=5+a \\ a+a=-5-5,a-a=5-5 \\ 2a=-10,0=0 \\ \frac{2a}{2}=\frac{-10}{2},0=0 \\ a=-5,0=0 \end{gathered}

Hence,

The final answer is

a\leq-5

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lisov135 [29]

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Step-by-step explanation:

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