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2 years ago

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Help will give Brainly points

1 answer:

atroni [7]2 years ago

5 0

The answer is B there you go have a nice day

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Given that OA = 2x + 9y, OB = 4x + 8y and CD = 4x - 2y, explain the geometrical relationships between the straight lines AB and

Step2247 [10]

Answer:

The geometrical relationships between the straight lines AB and CD is that they have the same slope

Step-by-step explanation:

Given

$OA = 2x + 9y$

$OB = 4x + 8y$

$CD = 4x - 2y$

Required

The relationship between AB, CD

Since AB is a straight line and O is the origin, then:

$AB = (c - a)x + (d - b)y$

Where:

$OA = ax + by$ ====> $OA = 2x + 9y$

$OB = cx + dy$ ====> $OB = 4x + 8y$

This implies that:

$a =2$ $b = 9$ $c = 4$ $d = 8$

So:

$AB = (c - a)x + (d - b)y$

$AB = (4 - 2)x + (8 - 9)y$

$AB = 2x -y$

So, we have:

$AB = 2x -y$

$CD = 4x - 2y$

Calculate the slope (m) of $AB\ and\ CD$

$m = \frac{Coefficient\ of\ y}{Coefficient\ of\ y}$

For AB

$m_1 = \frac{-1}{2}$

$m_1 = -\frac{1}{2}$

For CD

$m_2 = \frac{-2}{4}$

$m_2 = \frac{-1}{2}$

$m_2 = -\frac{1}{2}$

By comparison:

$m_1 = m_2 = -\frac{1}{2}$

This implies that both lines have the same slope

8 0

3 years ago

What is the area of the figure?<br> 118 in<br> 48 in<br> 128 in<br> 108 in

Talja [164]

Answer:

108 In

Step-by-step explanation:

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2 years ago

Jacob is calculating the amount of time it takes a rocket to get to the moon. The moon is around 239,000 miles from earth. How m

spin [16.1K]

Answer: so D 956 ✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅✅

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2 years ago

2.Solve x squared - 4x by Factoring

777dan777 [17]

Answer:

Step-by-step explanation:

hello:

x²-4x=0 means : x(x-4)=0

x=0 or x-4=0

conclusion : x=0 and x= 4 ...answer : B

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3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago