Question

Someone please help me on this I'm unsure if my answer is correct

Answer 1

Answer:

A. length = 23 cm; width = 5 cm

Step-by-step explanation:

So if 4 times the width would be $4w$ and 3 more than would be $+ 3$, the equation would be $l = 4w + 3$. If the perimeter is 56, then the new equation, $2(4w + 3) + 2(w) = 56$ can be formed. This simplifies to $8w + 6 + 2w = 56$, then to $10w + 6 = 56$, then to $10w = 50$, and finally, $w = 5$. So the width is 5, and now plug it into the first equation.

$l = 4(5) + 3$, becomes $l = 20 + 3$, becomes $l = 23$.

So the dimensions are: length = 23 cm, width = 5 cm.

*And just to be sure, $2(23 + 5) = 2(28) = 56$ which is correct.