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Alex73 [517]
2 years ago
11

What’s the value of x?

Mathematics
2 answers:
jeyben [28]2 years ago
8 0
It’s 115 cuz when two parallel lines are cut by a transversal line, the corresponding angles are always equal or congruent ;)
aleksandr82 [10.1K]2 years ago
6 0

Answer:

the value of x is 115

Step-by-step explanation:

hope I helped

please mark me as brainlyst

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What is the area of the circle?
Bumek [7]

Answer:

363

Step-by-step explanation:

Formula for area of a circle

A = πr^2

Where r = radius

The circle has a given radius of 11

To find the area of the circle we simply substitute r in the formula with the value of the radius (11)

( Also note that the question says to use 3 for π )

A = πr^2

π = 3

r = 11

Substitute values in formula

A = (3)(11)^2

11^2 = 121

A = 121(3)

121(3) = 363

A = 363

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4 > 6*t

Number t refers to an unknown. In this case, t can only be 0, because 6*0 = 0, and 4 > 0 or four is greater than 0. 
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Step-by-step explanation:

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Help math homework both questions
-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin Ф = \dfrac{\textrm x}{\textrm e}

Or, Sin 45° =  \dfrac{\textrm x meters}{\textrm 1.2 meters}

Or, 0.707 × 1.2 meters = x

∴ x =  0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend =  Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

Or, Tan Ф = \dfrac{\textrm H}{\textrm y}

Or, Tan 22° =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, 0.4040 =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, y =  \dfrac{\textrm  10,000 feet}{\textrm 0.4040}

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So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

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