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Oxana [17]
3 years ago
14

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics
2 answers:
expeople1 [14]3 years ago
4 0

Answer:

PT and SQ

Step-by-step explanation:

IF two segments are perpendicular then they will create 90 degree angles

segment PR and segment SQ cross over each other and create 90 degree angles therefore segment PR is perpendicular to segment SQ

sashaice [31]3 years ago
4 0
Hmmmmmmmmmmmmmmmmmmmmmmmmhgc
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What is the solution -10 = 2a - 4
Simora [160]

Add 4 to both sides

-10 + 4 = 2a

Simplify -10 + 4 to -6

-6 = 2a

Divide both sides by 2

-6/2 = a

Simplify 6/2 to 3

-3 = a

Switch sides

<u>a = -3</u>

6 0
4 years ago
Read 2 more answers
X<br> −<br> 3<br> 4<br> =<br> 8<br> Which value of <br> x<br> satisfies this equation?
insens350 [35]
. the answer is x=42
5 0
3 years ago
Y = -8x2 + 665x – 5754
Burka [1]

Answer:

Is the -8x2 a -8x squared? Because the answer of this problem can be different.

Step-by-step explanation:

3 0
4 years ago
The regression equation Credits = 17.9 − 0.09 Work was estimated from a sample of 21 statistics students. Credits is the number
Readme [11.4K]

Answer:

Step-by-step explanation:

Hello!

Given the regression equation

Credit= 17.9 - 0.09 Work

That was estimated from a sample of n= 21 statistic students.

Y: number of college credits taken

X: number of hours worked per week at an outside job

a)

The estimation for the slope is -0.09

As you see the estimated slope is negative, this means that the association between the two variables is indirect or inverse. Meaning, when the number of Work increases, the number of Credit decreases. (negative regression)

The correct option is: "An increase in the number of hours worked per week decreases the expected number of credits."

b)

The estimation for the intercept is 17.9

In general, the intercept is the estimated average of Y when X=0. You can interpret the intercept of this equation as "the value of Credits earned by a student that does not work outside of school"

The correct option is: " The intercept is meaningful as a student may not have a job outside of school. "

c)

If Work=0, then Credit= 17.9 (As explained in item b)

By replacing the value in the equation: Credit= 17.9 - 0.09 * 0= 17.9

If Work=60, you replace it in the equation and:

Credit= 17.9 - 0.09 Work= 17.9-0.09*60= 12.5

If the student works 60 hs outside of school it is expected that he takes 12.5 college credits.

I hope this helps!

4 0
4 years ago
A certain article reported the following observations, listed in increasing order, on drill lifetime (number of holes that a dri
aleksklad [387]

Answer:

Sample mean =119.42

Median = 92

25% trimmed mean = 102.42

10% trimmed mean = 95.69

Step-by-step explanation:

Data in increasing order :

12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513

Total no. of observations = 50

Sample mean = \frac{\text{Sum of all observations}}{\text{Total number of observations}}

= \frac{5971}{50} = 119.42

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10% Trimmed Mean: We remove 5 values from each side

Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{4097}{40} = 102.42

25% Trimmed Mean: We remove 12 values from each side.

Trimmed set =  66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{2488}{26} = 95.69

6 0
3 years ago
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